Rename key in nested dictionary Python

Question

This Python dictionary exercise aims to help Python developers to learn and practice dictionary operations. All questions are tested on Python 3.

Table of Contents Show

Table of contents
Exercise 1: Convert two lists into a dictionary
Exercise 2: Merge two Python dictionaries into one
Exercise 3: Print the value of key ‘history’ from the below dict1 = {'Ten': 10, 'Twenty': 20, 'Thirty': 30} dict2 = {'Thirty': 30, 'Fourty': 40, 'Fifty': 50}0
Exercise 4: Initialize dictionary with default values
Exercise 5: Create a dictionary by extracting the keys from a given dictionary
Exercise 6: Delete a list of keys from a dictionary
Exercise 7: Check if a value exists in a dictionary
How do I change the key name in a nested dictionary in Python?
How do I change the key
How do you rename a key in a dictionary in Python?
Can you modify the keys in a dictionary Python?

Python dictionary is a mutable object, and it contains the data in the form of key-value pairs. Each key is separated from its value by a colon (

keys = ['Ten', 'Twenty', 'Thirty']
values = [10, 20, 30]

# empty dictionary
res_dict = dict()

for i in range(len(keys)):
    res_dict.update({keys[i]: values[i]})
print(res_dict)

2).

Dictionary is the most widely used data structure, and it is necessary to understand its methods and operations.

Also Read:

Python Dictionary
Python Dictionary Quiz

This Python dictionary exercise includes the following: –

It contains 10 dictionary questions and solutions provided for each question.
Practice different dictionary assignments, programs, and challenges.

It covers questions on the following topics:

Dictionary operations and manipulations
Dictionary functions
Dictionary comprehension

When you complete each question, you get more familiar with the Python dictionary. Let us know if you have any alternative solutions. It will help other developers.

Use Online Code Editor to solve exercise questions.
Read the complete guide to Python dictionaries to solve this exercise

sampleDict = {
    "class": {
        "student": {
            "name": "Mike",
            "marks": {
                "physics": 70,
                "history": 80
            }
        }
    }
}

# understand how to located the nested key
# sampleDict['class'] = {'student': {'name': 'Mike', 'marks': {'physics': 70, 'history': 80}}}
# sampleDict['class']['student'] = {'name': 'Mike', 'marks': {'physics': 70, 'history': 80}}
# sampleDict['class']['student']['marks'] = {'physics': 70, 'history': 80}

# solution
print(sampleDict['class']['student']['marks']['history'])

Exercise 4: Initialize dictionary with default values

In Python, we can initialize the keys with the same values.

Given:

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

0

Expected output:

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

1

Show Hint

Use the

dict1 = {'Ten': 10, 'Twenty': 20, 'Thirty': 30}
dict2 = {'Thirty': 30, 'Fourty': 40, 'Fifty': 50}

1 method of dict.

Show Solution

The

dict1 = {'Ten': 10, 'Twenty': 20, 'Thirty': 30}
dict2 = {'Thirty': 30, 'Fourty': 40, 'Fifty': 50}

1 method returns a dictionary with the specified keys and the specified value.

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

2

Exercise 5: Create a dictionary by extracting the keys from a given dictionary

Write a Python program to create a new dictionary by extracting the mentioned keys from the below dictionary.

Given dictionary:

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

3

Expected output:

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

4

Show Hint

Iterate the mentioned keys using a loop
Next, check if the current key is present in the dictionary, if it is present, add it to the new dictionary

Show Solution

Solution 1: Dictionary Comprehension

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

5

Solution 2: Using the

keys = ['Ten', 'Twenty', 'Thirty']
values = [10, 20, 30]

# empty dictionary
res_dict = dict()

for i in range(len(keys)):
    res_dict.update({keys[i]: values[i]})
print(res_dict)

4 method and loop

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

6

Exercise 6: Delete a list of keys from a dictionary

Given:

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

7

Expected output:

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

8

Show Hint

Iterate the mentioned keys using a loop
Next, check if the current key is present in the dictionary, if it is present, remove it from the dictionary

To achieve the above result, we can use the dictionary comprehension or the

dict1 = {'Ten': 10, 'Twenty': 20, 'Thirty': 30}
dict2 = {'Thirty': 30, 'Fourty': 40, 'Fifty': 50}

4 method of a dictionary.

Show Solution

Solution 1: Using the

dict1 = {'Ten': 10, 'Twenty': 20, 'Thirty': 30}
dict2 = {'Thirty': 30, 'Fourty': 40, 'Fifty': 50}

4 method and loop

{'Ten': 10, 'Twenty': 20, 'Thirty': 30}

9

Solution 2: Dictionary Comprehension

keys = ['Ten', 'Twenty', 'Thirty']
values = [10, 20, 30]

res_dict = dict(zip(keys, values))
print(res_dict)

0

Exercise 7: Check if a value exists in a dictionary

We know how to check if the key exists in a dictionary. Sometimes it is required to check if the given value is present.

How do I change the key name in a nested dictionary in Python?

To change a single dictionary just reference the dictionary you want to change. And if you want to change yes entries across all the dicts you have to a loop over dict. values . Note that this won't maintain the order of the keys.

How do I change the key

Use the built-in update() method to merge the keys and values of one nested dictionary into another. Note that this method blindly overwrites values of the same key if there's a clash.