Fungsi f : R → R dan g : R → R ditentukan oleh f(x 2x 3 dan g(x x 2 x 2 Nilai gof 4 adalah))

F(x) = 2x +3 --> f⁻¹(x) = (x - 3)/2g(x) = (x+1)/(x-2) --> g⁻¹(x) = (2x+ 1)/(x-1)a) (gof)⁻¹(x) = f⁻¹ o g⁻¹ (x) = { 2x+1)/(x-1) - 3}/2= ((2x-1)-3(x-1)} / 2(x-1)= (2x-1- 3x + 3) /(2x - 2)= (-x +2) /(2x -2)(fog)⁻¹ (x)= g⁻¹ o f⁻¹(x)g⁻¹{(x-3)/2} = { 2(x-3)/2 + 1 } / {(x-3)/2) -1}= (4(x-3) + 2)/((x-3) - 2}= (4x - 12 + 2) / (x -3 - 2)= (4x - 10)/(x- 5)b.(gof)⁻¹(2) = (-2+2)/(4-2)= 0(fog)⁻¹(2)= (4(2) -10 )/(2-5)=  - 2/-3 = 2/3